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We've seen many a cases where the "last good" x/y/z is desynced from the x/y/z that is checked for moving too fast. Theory is that when you have multiple movement packets queued up, and the player is teleported after the first then the 2nd and 3rd come in, it is triggering a massive movement velocity. This will ensure that the servers position is synchronized anytime player is te Fixes #3258
35 lines
No EOL
1.5 KiB
Diff
35 lines
No EOL
1.5 KiB
Diff
From 0000000000000000000000000000000000000000 Mon Sep 17 00:00:00 2001
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From: Aikar <aikar@aikar.co>
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Date: Sun, 3 May 2020 14:25:55 -0400
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Subject: [PATCH] Sync position on teleportation
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We've seen many a cases where the "last good" x/y/z is desynced from
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the x/y/z that is checked for moving too fast.
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Theory is that when you have multiple movement packets queued up,
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and the player is teleported after the first then the 2nd and 3rd come in,
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it is triggering a massive movement velocity.
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This will ensure that the servers position is synchronized anytime player is teleported.
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diff --git a/src/main/java/net/minecraft/server/PlayerConnection.java b/src/main/java/net/minecraft/server/PlayerConnection.java
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index 02bda8bee4..a188d9f3b6 100644
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--- a/src/main/java/net/minecraft/server/PlayerConnection.java
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+++ b/src/main/java/net/minecraft/server/PlayerConnection.java
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@@ -0,0 +0,0 @@ public class PlayerConnection implements PacketListenerPlayIn {
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this.o = this.teleportPos.x;
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this.p = this.teleportPos.y;
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this.q = this.teleportPos.z;
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+ this.syncPosition(); // Paper
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if (this.player.H()) {
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this.player.I();
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}
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@@ -0,0 +0,0 @@ public class PlayerConnection implements PacketListenerPlayIn {
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this.A = this.e;
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this.player.setLocation(d0, d1, d2, f, f1);
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+ this.syncPosition(); // Paper
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this.player.playerConnection.sendPacket(new PacketPlayOutPosition(d0 - d3, d1 - d4, d2 - d5, f - f2, f1 - f3, set, this.teleportAwait));
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}
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--
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